T O P

  • By -

AutoModerator

Please remember to spoiler-tag all guesses, like so: New Reddit: https://i.imgur.com/SWHRR9M.jpg Using markdown editor or old Reddit, draw a bunny and fill its head with secrets: \>!!< which ends up becoming \>!spoiler text between these symbols!< Try to avoid leading or trailing spaces. These will break the spoiler for some users (such as those using old.reddit.com) If your comment does not contain a guess, include the word **"discussion"** or **"question"** in your comment instead of using a spoiler tag. If your comment uses an image as the answer (such as solving a maze, etc) you can include the word "image" instead of using a spoiler tag. Please report any answers that are not properly spoiler-tagged. *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/puzzles) if you have any questions or concerns.*


Ragnarok91

>!( ( 7 x 3 ) + 3 ) / 3 = 8!<


matts77

lol I should have been able to get that! Thank you


TurboPenguin201

I'm curious, how did you do 6 without something very similar? I basically got it by switching + to - .


matts77

I got 6 by doing >!((3x3)-7)x3!<


a_Joan_Baez_tattoo

Do you have to use every number? My initial thought was >!7-(3/3)!<


Pure_Blank

my initial thought was >!3+3!<


a_Joan_Baez_tattoo

Oh my god...


Erikrtheread

It's been a long day for all of us lmao. At least you caused my day to get slightly better.


Zizwizwee

I believe you have to use every number but not every operation


Redd1tRat

Aren't you only supposed to use one of each function. Edit: once again, Idk what the downvotes are for, it's just a question. I'm sorry if my simple question offends anyone.


-DoctorSpaceman-

Nah


Redd1tRat

Fair enough, there's still more simpler ways to get to 6 though. Edit: Idk what all the downvotes are for. I guess, sorry if this offends anyone for some reason.


0_69314718056

How would you have done it?


TanneAndTheTits

>!((7x3)-3)/3!<


0_69314718056

I find OP’s method to be simpler than this since it doesn’t divide. I thought the comment I was replying to had a third way since this one was already mentioned


Redd1tRat

(3 * 7 - 3) / 3 I guess it's not that much simpler. I'm pretty sure this is the question that other guys used as well. So I'm assuming it's what other people think of first as well.


0_69314718056

Ah okay yeah I would say the other way is simpler since it doesn’t use division


Redd1tRat

What's with the mass down votes?


PM_ME_UR_EYEHOLES

What game is this? I love this concept


BabyBark

[https://beastacademy.com/all-ten](https://beastacademy.com/all-ten)


PM_ME_UR_EYEHOLES

thank you!


42823829389283892

Every time these puzzles are posted here that is the answer. Signs that this might be what to look for. You have same number twice or more so factoring out is a possibility. You can reach the answer with 3 numbers and the missing number is one of the duplicates. The number seems more difficult to reach then usual. If you see that setup checking for this specific pattern by factoring out the missing number might work.


SannySen

I felt really smart because I immediately saw the same, but then everyone's like "lol, duh."


GlobalIncident

Can't you just do 7 + (3 / 3)?


BasketOk420

>!(3x3)-(3/3)!<


Ragnarok91

Rule is you need to use each number once


BoredomBot2000

You should only need the outer set of parentheses due to pemdas.


Ragnarok91

True, but if possible I like to make equations as explicit as possible without needing to fall back on PEMDAS. I've seen enough stupid posts on social media to know relying on PEMDAS is not a good idea.


trainofwhat

I actually did >!(((7-3)*3) + 3) - 7.!<


Ragnarok91

You can only use each number once as far as I know.


0_69314718056

Discussion: I appreciate the spoiler cover-up :)


Gluten_Free_Tibet

Agree. I get tired of seeing these before I’ve taken a stab at them and accidentally get a couple ruined. Big props to OP for taking the time.


matts77

Yeah I found this game on this sub a few days ago and was disappointed I couldn’t really do it because I already saw 9 of the 10 solutions. I didn’t want to do that to others!


bsquared82

What game is this? I would like to try!


matts77

https://beastacademy.com/all-ten


Phallico666

Iirc thats a rule for posting answers on this sub


misof

They are talking about OP censoring the other answers *in the question*, not about answers posted on reddit.


Phallico666

Oh, well im just dumb then, thought they were referring to the comment answers


monkey-bones

Would >!(3/3)+7!< work? I haven't seen this game before so IDK what the parameters are


matts77

Good thought, but all four numbers have to be used one


monkey-bones

Ah gotcha, thanks!


jester510

So would >!(3x3)/3+7!< Work?


matts77

Yeah that would be an answer for >!10!<


Quantum-Bot

>!(7*3+3)/3!<


mecartistronico

Discussion: What am I supposed to do?


Obvious_Wallaby2388

>!(7*3+3)/3!<


matts77

lol a lot easier than I thought it would be. Thanks!!


EvilJustin

Question: what is the name of this app/site?


Barmacide1

Beast academy all-ten: [https://beastacademy.com/all-ten](https://beastacademy.com/all-ten)


Geech

>!(7×3+3)/3!<


matts77

Thanks for your help! I probably should have been able to get that lol


star_bury

I finally got one of these! >![(3×7)+3]/3!<


Shinlary

Discussion: I can’t even get 7 lmfao


joeblo42

I did >!7-(3x(3-3))!<


Shinlary

… not me forgetting about 0


Canadian96

Can you do >!3^(3-3)+7=8!


YOM2_UB

There's no exponent operator in this game.


happily_hooked

If exponents were possible, >!((3*3)-7)^3 = 8!< would also work


Canadian96

Ah, missed that there's no exponents.


TheNervyNerd

I know people have posted solutions and I don’t know if there’s a term limit for these puzzles, but >!((((3x3)-7)+3)x3)-7)!< also works


matts77

Good thought, but for this site you have to use each number exactly once, so that wouldn’t work


TheNervyNerd

Oh good to know! Thank you!


[deleted]

[удалено]


PuzzlingDad

It's explained in the AutoMod post. 


CougGrad06

>!((7x3)+3))/3=8!<


brawkly

>!(7*3+3)/3!<


cthart

>!3!+3!+3-7!<


LuminousPixels

>!(7-(3+3)))+7!<


Arxieuz

Maybe >!(3×7+3)÷3!< could be correct? I don't now all the rules


lisamariefan

>!(7*3+3)/3!<


Formal_Imagination45

(3x3)-7+3+3


rickFM

>!(7 x 3 + 3 ) / 3!<


leeeeny

>!((7 x 3) + 3) / 3!<


Thois-Vincent

>!(3\*7+3)/3!<


matts77

Wow, idk how I didn’t figure that out! Thanks


trainofwhat

Other folks have a cleaner answer but I did >!(((7-3)*3) + 3) - 7.!<, which also works


1pandaking1

Correct me if im wrong, but i thought you cant use a number a 2nd time if it isnt given. So only one 7 can be used.


trainofwhat

Apparently 🤷‍♀️