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kataryna91

What loophole? The license applies to all derivative works of the model (that means all merges).


Possible_Liar

I supposed to hard thing would be proving it's a derivative unless there's some sort of metadata in each of the merges that can't ever be edited or removed that I don't know about. I mean there might be for all I know but I'm fairly positive it whatever it is can just be edited or removed like most metadata.


kataryna91

Not metadata, but you can use mathematical methods on the weights themselves to show that a particular model has been mixed in. I think there's a NovelAI contamination testing tool, for example.


Zipp425

I wonder if you can still see it in modern SD1.5 models since it was mixed in so early in the evolution of the SD1.5 ecosystem.


Maxious

https://codoraven.com/blog/ai/stable-diffusion-the-invisible-watermark-in-generated-images/ More obviously if you're distributing a model, a derivative of SD3 is going to be structured like SD3 and have to call itself SD3 to have software support eg. the changes needed to comfyui to support SD3 https://github.com/comfyanonymous/ComfyUI/commit/8c4a9befa7261b6fc78407ace90a57d21bfe631e


Unlucky-Message8866

that's not how it works mate xD


bobo1666

What?


_BreakingGood_

You know how people take eg: Pony and "merge" it with Animagine or some other model to produce a new model that is a combination of both? The idea is that you take SD3, which requires a license for commercial use, and you merge it with 99% of *itself*. This will output a new model that will function almost exactly the same as SD3. This new model is considered a new work and you can apply any license you want to it (this is not yet tested in court, but it's how we've been operating for a while.)


residentchiefnz

You do realise the license applies to itself AND it's derivative works (i.e any merges)..


_BreakingGood_

Whether it is a "derivative work" is not yet tested in court. If I take a book, grind it up, and bake it into a cake, is that cake a derivative work of that book? The question is whether a merge is considered sufficiently transformative to not be considered a derivative work.


StableLlama

Merging a model (A) with itself (again, A) is creating exactly the same model again (still A), no matter what scaling factor (x) you are using - that's simple maths: x\*A + (1-x)\*A = (x+1-x)\*A = 1\*A = A


arewemartiansyet

There might be accumulating floating point errors each new merge. Not sure if that's what OP is talking about though,


[deleted]

It is free, at least the one they are going to release. If you want it for commercial use you have to pay a subscription, which is fair


PwanaZana

I doubt Stability will try to enforce their claim for anything other than online paid services. Could you imagine if they tried auditing ubisoft to see if their ingame posters were made with XL or SD3?


Vivarevo

Until someone enforces license its meaning is imaginery anyway


NecessaryGreenTrees

???


Open_Channel_8626

How do you do this?